英文字典中文字典


英文字典中文字典51ZiDian.com



中文字典辞典   英文字典 a   b   c   d   e   f   g   h   i   j   k   l   m   n   o   p   q   r   s   t   u   v   w   x   y   z       







请输入英文单字，中文词皆可：


请选择你想看的字典辞典：
单词字典翻译
ancilla查看　ancilla　在百度字典中的解释百度英翻中〔查看〕
ancilla查看　ancilla　在Google字典中的解释Google英翻中〔查看〕
ancilla查看　ancilla　在Yahoo字典中的解释Yahoo英翻中〔查看〕

安装中文字典英文字典查询工具!


中文字典英文字典工具:
选择颜色:
输入中英文单字

































































英文字典中文字典相关资料:


  • terminology and notation - What counts as an ancilla qubit? - Quantum . . .
    The general meaning of ancilla in ancilla qubit is auxiliary In particular, when people write about "constant input" what they mean is that, for a given algorithm -which has a purpose, such as finding the prime factors of an input number, or effecting a simple arithmetic operation between two input numbers the value of the ancilla qubits will be independent of the value of the input
  • quantum algorithms - Ancilla intuition, when to use them, how to . . .
    In LCU, the ancilla system is used to prepare a superposition to probabilistically apply the terms in the LC based on the relative weights of the coefficients in the LC Then uncomputing the ancillary register and measuring a signal state (typically the all zero state) tells us that the state on the register corresponded to a normalized
  • Removing ancilla qubits in Qiskit circuit - Quantum Computing Stack . . .
    I want to remove the ancilla qubits from my quantum circuit in Qiskit My MWE below contains four qubits: psi0, psi1, anc0, anc1 I want to keep psi0 and psi1 qubits and remove ancillas anc0, anc
  • How to reset ancilla after swapping when original ancilla flipping . . .
    It means that the ancilla now stores whether exactly one of the groups is in the $|00\rangle$ state (boot that if both are in this state, there's no need to swap them) apply a SWAP gate between the first group and the second one controlled off the ancilla being in state $|00\rangle$ redo the first step
  • reversible computation - To what degree could additional ancilla qubits . . .
    To implement this brute force search we have to initialize exponential number of ancilla qubits A single layer of 2-qubit gates can double the number of affected qubits, so it seems a polynomial number of layers should be enough to implement the search However, the question "Do we really need the exponential amount of ancillas?"
  • Why doesnt reading the ancilla qubit in Quantum Error Correction kill . . .
    The ancilla tells us about the errors, not the underlying logical state (In classical terms the ancilla in this example is a "parity check bit" - the quantum difference being we that we have to generate this bit coherently, without revealing entangling with any further information about the underlying bits )
  • Why do we use ancilla qubits for error syndrome measurements?
    By measuring ancilla qubits we can know what has happened to the qubits without actually knowing the values of the qubits: this enables us to correct errors in a non-destructive way, and carry on with our quantum operation
  • How are ancilla qubits physically prepared and measured?
    There, you can take an ancilla qubit, entangle it to the circuit, and its measurement result gives you the parity of some of the qubits This parity does not collapse the state (i e if ZZ = 1, you can still be in a superposition of, e g $|00\rangle + |11\rangle$ ), but rather projects it to a specific subspace
  • How many ancilla qubits to use with Multiple-Control Toffoli (mct) gate . . .
    The Multiple-Control Toffoli (mct) gate takes as input: 1 a register containing the control qubits, 2 the target qubits and 3 a register containing ancilla qubits I don't know how many a
  • Implementing Odd Permutations Without Ancilla Bit
    It's true that you can bypass the parity barrier by using quantum operations, but doing so has a high cost Bootstrapping an ancilla qubit will easily consume 5x more T gates than just starting with an ancilla qubit Also, keep in mind that, in the context of a large computation laid out on a 2d grid, there are already ancilla qubits everywhere





中文字典-英文字典  2005-2009