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  • The start of x86: Intel 8080 vs Intel 8086?
    Fortunately, the 8086 registers are effectively a superset of the 8080 registers, so we can map A to AL, BC to CX, DE to DX and HL to BX (this ends up with the registers in a non-intuitive order, as HL can be used for indirect memory addressing, which is better supported using BX than the other general purpose registers on the 8086 -- but note
  • Why is the Intel 8086 CPU called a 16-bit CPU?
    The 8086 Family User’s Manual isn’t quite so categorical, but it does describe the 8086 as an “8 16 bit general-purpose micro-processor” with a “16-bit external data path”; and it specifies that all CPUs in the 8086 family “operate on both 8-and 16-bit data types” with “internal data paths are at least 16 bits wide
  • 8086 - x86 memory alignment - Retrocomputing Stack Exchange
    For the 8086, unaligned word loads (first byte at an odd address) require two memory accesses, but an aligned word (first byte at an even address) can be loaded in one This is excellently explained by answers over at Electronics Stack Exchange: ‘Accessing odd address memory locations in 8086’
  • How does single-stepping on the 8086 interact with internal and . . .
    The 1979 version of the 8086 family user's manual is available at different places in the internet, see 1,2,3 It seems there is no newer version available This manual documents the single-stepping feature in figure 2-29 on page 2-23 and figure 2-31 on page 2-27 Are these diagrams accurate?
  • history - Could the Intel 8086 CPU have many segments in memory of the . . .
    The Intel 8086 CPU could address up to 1 MB of memory using segmentation, and this CPU have 4 segment registers, which are CS and SS and DS and ES Each segment in memory can have a maximum size of 64 KB, which means that if all 4 segment registers are used, then 256 KB of memory would be used, which leaves 768 KB of memory unused
  • 8086 - Difference between Intel 8087 and 8089 opcodes - Retrocomputing . . .
    The 8086 must wait for Busy before executing any other 8089 command When done, the 8089 will reset the Busy-Flag 0h, signalling that the channel is finished The same happens as well when a channel program stops at a defined point (usually by a HALT instruction) The Busy-Flag can be polled by the 8086 as the CB is always in shared memory
  • Most modern C compilers targeting DOS 8086, running on DOS 8086 (16-bit)
    I'm aware of the following C compilers, but they are not answers to my question, because they don't run on DOS 8086: OpenWatcom: I've successfully compiled C code targeting DOS 8086 with the most recent build 2022-11-22 on DOSBox with 5 MiB of memory Arguably OpenWatcom is the most modern C C++ compiler still targeting DOS 8086
  • 8086 - Difference between the 8255 and 8042 PPIs - Retrocomputing Stack . . .
    A special feature of the 8042 is a built-in bus interface to allow it to easily integrate with Intel master CPUs like the 8086 - but it doesn't necessarily nead to run along one of them The 8255 however, is a completely different thing - It's a peripheral chip to the 80xx line of CPUs that provides 3 byte-wide digital I O ports
  • What does an ADC (add with carry) instruction following ADD do?
    As others have explained, ADC adds its two operands and the carry bit, storing the result in the first operand Like ADD, it sets the carry bit as appropriate: adding two n-bit values produces a (n+1)-bit result, and the (n+1)th bit goes in the carry flag (counting from the least-significant bi
  • 80386 - How can a 32-bit x86 CPU start with reset vector 0xFFFFFFF0 . . .
    On reset, in a 8086 8088, the CS register will be 0xFFFF and IP register will be 0x0000 It will be slightly different values and map to different memory addresses based on CPU On a real 8086 8088 CPU with only segmented real mode available, that is right below maximum addressable 1 MB, address 0xFFFF0





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